Question

Calcule:
(c³+4c²+c)(c-1)=

Answer 1

(c³+4c²+c)(c-1)=
$c ^{4} -c ^{3} +4c ^{3} -4c ^{2} +c ^{2} -c$

$c ^{4} +3c ^{3} -3c ^{2} -c$