Question

Calcule

c) $\sqrt{0} - \sqrt[5]-{1}$

d)$\sqrt[3]{} -\frac{8}{27} - \sqrt{} \frac{25}{64}$

Answer 1

c) √0 = 0
$\sqrt[5]{-1 }$ = -1

0 - (-1) = 0 + 1 = 1

d) ∛ - $\frac{8}{27}$ = $\frac{2}{3}$
√$\frac{25}{64} = \frac{5}{8}$

$\frac{2}{3} - \frac{5}{8} = \frac{16-15}{24} = \frac{1}{24}$