Question

calcule C n,p=n!p!(n-p)! onde n =9 e p =6​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{C_{n,p} = \dfrac{n!}{p!(n - p)!}}$

$\mathsf{C_{9,6} = \dfrac{9!}{6!(9 - 6)!}}$

$\mathsf{C_{9,6} = \dfrac{9.8.7.\not6!}{\not6!.3!}}$

$\mathsf{C_{9,6} = \dfrac{504}{6}}$

$\boxed{\boxed{\mathsf{C_{9,6} = 84}}}$