Question

Calcule:

B).. $\frac{ 3^{0} + (- 2)^{2} - \frac{(1)}{(3)} -^{1} } {\frac{(1)}{(2)}-^{2}}$

Answer 1

Observe que:
$\\3^0=1\\ \\(-2)^2=4\\ \\(\frac{1}{3})^{-1}=3^1=3\\ \\(\frac{1}{2})^{-2}=2^2=4$

Agora, substituindo os valores:
$\frac{3^0+(-2)^2-(\frac{1}{3})^{-1}}{(\frac{1}{2})^{-2}}= \frac{1+4-3}{4}= \frac{2^{:2}}{4_{:2}} = \frac{1}{2}$

Answer 2

$\dfrac{ 3^{0} + (- 2)^{2} - ( \frac{1}{3}) ^{-1} } {(\frac{1}{2})^{-2}} = \\ \\ \\ \dfrac{ 3^{0} + (- 2)(-2) - ( \frac{3}{1}) ^{+1} } {(\frac{2}{1})^{+2}} = \\ \\ \\ \dfrac{ 3^{0} + (+4) - \frac{3}{1} } {(\frac{2^2}{1})} = \\ \\ \\ \dfrac{ 3^{0} + (+4) - 3 } {4} = \\ \\ \\ \dfrac{ 1 + 4 - 3 } {4} = \dfrac{ 5-3 } {4} = \dfrac{2 } {4} = \boxed{ \dfrac{1} {2}}$


Até outra vez!!!!