Question

Calcule as somas
(4x+4)+(6x-1)=
(2a+4b)+(8a-6b)=
(6y+2x-1)+(2y+8x+2)=
(3a-5b+c)+(6a-b-2c)+(2a+3b-3c)=

Answer 1

(4x+4)+(6x-1)= 10x + 3

(2a+4b)+(8a-6b)= 10a - 2b

(6y+2x-1)+(2y+8x+2)= 8y+ 10y + 1

(3a-5b+c)+(6a-b-2c)+(2a+3b-3c)= 11a - 3b - 4c