Question

Calcule as somas
(4x+4)+(6x-1)=
(2a+4b)+(8a-6b)=
(6y+2x-1)+(2y+8x+2)=
(3a-5b+c)+(6a-b-2c)+(2a+3b-3c)=

Answer 1

(4x+4)+(6x-1)= 4x+6x +4-1==> 10x +3
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(2a+4b)+(8a-6b)= 2a+4b+8a-6b ==> 10a-2b
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(6y+2x-1)+(2y+8x+2)=  6y+2x-1+2y+8x+2 ==> 8y+10y+1
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(3a-5b+c)+(6a-b-2c)+(2a+3b-3c)= 

3a-5b+c+6a-b-2c+2a+3b-3c

11a - 3b - 4c