Question

Calcule as seguintes potências com expoente negativo:
$10 ^{-2}$

$-5/8 ^{-2}$

$-3/2^ {-3}$

$(-3)^{-3}$

Answer 1

$10^{-2}= \frac{1}{10^2} = \frac{1}{100} \\ \\ (- \frac{5}{8} )^{-2}=(- \frac{8}{5} )^2=+ \frac{64}{25} \\ \\ (- \frac{3}{2} )^{-3}=(- \frac{2}{3} )^3=- \frac{8}{27} \\ \\ (-3)^{-3}=(- \frac{1}{3} )^3=- \frac{1}{27}$