Question

Calcule as seguintes potências: a) 8³ b) (4/3 )³ c) (-3/5)³ d) (- 2/7)³ *

Answer 1

→ Cálculo :

A) 8³ = 8 · 8 · 8 = 512

B) (4/3)³ = 4³/3³ = 64/27

C) (-3/5)³ = -(3/5)³ = -3³/5³ = -27/125

D) (-2/7)³ = -(2/7)³ = -2³/7³ = -8/343

Answer 2

Olá! (^_-)

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${ \large \displaystyle \sf \: \sf a) \: {8 {}^{3} = 8 \times 8 \times 8 = \boxed{ \red{{ 512}}}}}$

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${ \large \displaystyle \sf \: \sf b) {\left ( \dfrac{4}{3} \right ) ^{3} = \frac{4 ^{3} }{3 ^{3} } = \boxed { \red{\frac{64}{27} }}}}$

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${ \large \displaystyle \sf \: \sf c) {\left ( - \dfrac{3}{5} \right ) ^{3} = - \left ( \dfrac{3}{5} \right ) ^{3} = - \frac{3^{3} }{5 ^{3} } = \boxed{ \red{- \frac{27}{125} }}}}$

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${ \large \displaystyle \sf \: \sf d) {\left ( - \dfrac{2}{7} \right ) ^{3} = - \left ( \dfrac{2}{7} \right ) ^{3} = - \frac{2^{3} }{7 ^{3} } = \boxed{ \red{- \frac{8}{343} }}}}$

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Espero ter ajudado! ❤️