Question

calcule as seguintes potências: A) (1a²b²/2)³= B) (-mn²/4)³= C) (-0,3ay^4)²=

Answer 1

Oie, Td Bom?!

A)

$= ( \frac{1a {}^{2} b {}^{2} }{2} ) {}^{3}$

$= ( \frac{a {}^{2} b {}^{2} }{2} ) {}^{3}$

$= \frac{a {}^{6}b {}^{6} }{8}$

B)

$= ( - \frac{mn {}^{2} }{4} ) {}^{3}$

$= - ( \frac{mn}{4} ) {}^{3}$

$= - \frac{(mn) {}^{3} }{4 {}^{3} }$

$= - \frac{m {}^{3} n {}^{3} }{64}$

C)

$= ( - 0,3ay {}^{4} ) {}^{2}$

$= ( - 0,3) {}^{2} \: . \: a {}^{2} y {}^{8}$

$= 0,3 {}^{2} \: . \: a {}^{2} y {}^{8}$

$= ( \frac{3}{10} ) {}^{2} \: . \: a {}^{2} y {}^{8}$

$= \frac{9}{100} a {}^{2} y {}^{8}$

Att. Makaveli1996