Question

calcule as seguintes potências:

A) (-12 m n3 ) 4 =

B) (12 a2 b ) 2 =

C) (-3 x2 y3 ) 3 =

D) (0,2 y2 z ) 5 =

E) (-x2 y3 ) 8 =

F)
$( \frac{ {1a}^{2} }{} \frac{}{2} \frac{ {b}^{2} }{} ) {}^{3} =$


G)
$( \frac{ - m}{4} \frac{ {n}^{3} }{?}) {}^{3} =$


H)
$( - 0.3 \:a \: {y}^{4} ) {}^{2}$
​

Answer 1

Explicação passo-a-passo:

a) $\sf (-12mn^3)^4=\red{20736m^4n^{12}}$

b) $\sf (12a^2b)^2=\red{144a^4b^2}$

c) $\sf (-3x^2y^3)^3=\red{-27x^6y^9}$

d) $\sf (0,2y^2z)^5=\red{0,00032y^{10}z^5}$

e) $\sf (-x^2y^3)^8=\red{x^{16}y^{24}}$

f) $\sf \Big(\dfrac{a^2b^2}{2}\Big)^3=\red{\dfrac{a^6b^6}{8}}$

g) $\sf \Big(\dfrac{-mn}{4}\Big)^3=\red{\dfrac{-mn^3}{64}}$

h) $\sf (-0,3ay^4)^2=\red{0,09a^2y^8}$