Question

Calcule as seguintes equações exponenciais:
a) 9 ( x como expoente)= 1/3
b) (2/3)x= 8/27
c) 5x= raiz de 5
d) (9/25)2x = 5/3
e) 32x+3 = 3 (na raiz) raiz de 2

Answer 1

a) 9ˣ = 1/3
(3²)ˣ = 3⁻¹
2x = -1
x = -1/2

b) (2/3)ˣ = 8/27
(2/3)ˣ = (2/3)³
x = 3

c) 5ˣ = √5
5ˣ = 5¹/²
x = 1/2

d) (9/25)²ˣ = 5/3
[(3/5)²]²ˣ = 5/3
[(5/3)⁻²]²ˣ = (5/3)¹
-4x = 1 *(-1)
4x = -1
x = -1/4

e) 32ˣ⁺³ = ∛2
(2⁵)ˣ⁺³ = 2¹/³
5x + 15 = 1/3
5x = 1/3 - 15
15x = 1 -  45
15x = -44
x = -44/15

Answer 2

Resposta:

a) 9ˣ = 1/3

(3²)ˣ = 3⁻¹

2x = -1

x = -1/2

b) (2/3)ˣ = 8/27

(2/3)ˣ = (2/3)³

x = 3

c) 5ˣ = √5

5ˣ = 5¹/²

x = 1/2

d) (9/25)²ˣ = 5/3

[(3/5)²]²ˣ = 5/3

[(5/3)⁻²]²ˣ = (5/3)¹

-4x = 1 *(-1)

4x = -1

x = -1/4

e) 32ˣ⁺³ = ∛2

(2⁵)ˣ⁺³ = 2¹/³

5x + 15 = 1/3

5x = 1/3 - 15

15x = 1 - 45

15x = -44

x = -44/15

Explicação passo-a-passo: tá ai