Question

Calcule as raizes reais da função f(x) = x²+3x - 10 se existir

Answer 1

Resposta:

S={( -5 ; 2)}

Explicação passo-a-passo:

f(x) = x²+3x -10

a=1

b=3

c=-10

∆=b²-4.a.c

∆=(3)²-4.(1).(-10)

∆=9+40

∆=49

x'=[-(+3)+√49]/2.(1)

x'=[-3+7]/2

x'=4/2

x'=2

x"=[-(+3)-√49]/2.(1)

x"=[-3-7]/2

x"=-10/2

x"=-5

Espero ter ajudado!

Answer 2

Resposta:

$x^{2}+3x-10=0\\ \\delta=b^{2}-4.a.c\\ \\delta=3^{2}-4.1.(-10)\\ \\delta=9-(-40)\\ \\delta=9+40=49\\ \\x=\frac{-b+-\sqrt{delta}}{2.a}\\ \\x=\frac{-3+-\sqrt{49}}{2.1}\\ \\x=\frac{-3+-7}{2}\\ \\x'=\frac{-3+7}{2}~~~~~~x'=\frac{4}{2}~~~~~~x'=2\\ \\x''=\frac{-3-7}{2}~~~~~x''=\frac{-10}{2}~~~~~~x''=-5\\ \\as~raizes~reais~sao:\left \{ {{-5;~~2} \ {}\} \right.$