Question

CALCULE AS RAIZES ETILIZANDO O METODO DA FATORAÇAO a) 196 b)225 c)300 d)441 e)529 f)600 g)1080 h)1000 i)1225 j)1300 k)1600 l)1700
ME AJUDEM VALE NOTA POR FAVOR ALGUEM PODE ME AJUDAR ??

Answer 1

$a) \sqrt{196} = \sqrt{ 2^{2} . 7^{2} } =2.7=14 \\ \\ b) \sqrt{225} = \sqrt{ 3^{2}.5^2 } =3.5=15 \\ \\ c) \sqrt{300} = \sqrt{2^2.3.5^2} =2.5 \sqrt{3} =10 \sqrt{3} \\ \\ d) \sqrt{441} = \sqrt{3^2.7^2} =3.7=21 \\ \\ e) \sqrt{529} = \sqrt{23^2} =23 \\ \\ f) \sqrt{600} = \sqrt{2^3.3.5^2} = \sqrt{2^2.2.3.5^2} =2.5 \sqrt{2.3} =10 \sqrt{6}$

$g) \sqrt{1080} = \sqrt{2^3.3^3.5} = \sqrt{2^2.2.3^2.3.5} =2.3 \sqrt{2.3.5} =6 \sqrt{30} \\ \\ h) \sqrt{1000} = \sqrt{2^3.5^3} = \sqrt{2^2.2.5.5^2} =2.5 \sqrt{2.5} =10 \sqrt{10} \\ \\ i) \sqrt{1225} = \sqrt{5^2.7^2} =5.7=35 \\ \\ j) \sqrt{1300} = \sqrt{2^2.5^2.13} =2.5 \sqrt{13} =10 \sqrt{13} \\ \\ k) \sqrt{1600} = \sqrt{2^6.5^2} =2^3.5=8.5=40 \\ \\ l)\sqrt{1700} = \sqrt{2^2.5^2.17} =2.5 \sqrt{17} =10 \sqrt{17}$