Question

Calcule as raízes de cada equação

(2 x + 3)^2-9=12x


(3x-1)^2=1


(x-2).(x+4)=2.(x+4)


-15x+x^2=x^2+5.(x^2-3x)
..........3

Answer 1

Resposta:

Explicação passo-a-passo:

(2x+3)×(2x+3)-9=12x

4x^2+12x+9-9=12x

4x^2+12x-12x+9-9=0

4×^2=0

x^2=0/4

×.×=0

×=0

(3x-1)×(3x-1)=1

9x^2--6x+1=1

9x^2-6x+1-1=0

9x^2-6×=0

x'=0

x"=x.(9x-6)=0

9x=6

x=6/9

x=2/3

(x-2)×(x+4)=2×(x+4)

x^2+2x-8=2x+8

x^2+2x-8-2x-8=0

x^2-16=0

x^2=16

×=raíz quadrada de 16

x=4

-15x+x^2=x^2+5.(x^2-3x)

-15x+x^2=x^2+5x^2-15x

-15x+x^2-x^2-5x^2+15x=0

5x^2=0

x^2=0/5

x.x=0

x=0

Espero ter ajudado.Boa tarde !