Question

Calcule as raízes da função Quadrática f(x) = 3x² + x - 2​

Answer 1

$f(x) = 3x^2 + x - 2\\\\x = \frac{-1 \pm \sqrt{1^2 - 4.(-2).3}}{2.3}\\x = \frac{-1 \pm \sqrt{1 + 24}}{6}\\x = \frac{-1 \pm \sqrt{25}}{6}\\x = \frac{-1 \pm 5}{6}\\\\x_1 = \frac{-1 + 5}{6} = \frac{4}{6} = \frac{2}{3}\\x_2 = \frac{-1-5}{6} = \frac{-6}{6} = -1$

Resposta: -1 e $\frac{2}{3}$.