Question

Calcule as raizes da esquacoes x²–8x+7=0

Answer 1

Boa Noite !!!

$x^{2} - 8x + 7 = 0\\\\\Rightarrow coeficientes:\\\\ a = 1\\\\b = -8\\\\c = 7\\\\\Delta = b^2 - 4.a.c\\\\\Delta = (-8)^2 - 4.1.7\\\\\Delta = 64 - 28\\\\\Delta = 36\\\\x = \frac{-b\pm\sqrt{\Delta} }{2.a} \\\\x = \frac{8\pm6}{2} \\\\x' = \frac{14}{2} \\\\x' = 7\\\\x" = \frac{2}{2} \\\\x" = 1\\\\s = [7,1]$

Espero ter ajudado :-)

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Answer 2

Resposta ↓

Conjunto solução ⇒ s = {7, 1}

Explicação passo-a-passo:

x² - 8x + 7 = 0

Coeficientes :

a = 1

b = -8

c = 7

Δ = b² - 4.a.c

Δ = (-8)² - 4.1.7

Δ = 64 - 28

Δ = 36

$x = \cfrac{-b\pm\sqrt{\Delta} }{2.a} \\\\\\x = \cfrac{8 \pm 6}{2} \\\\\\x' = \cfrac{14}{2} \\\\\\x' = 7\\\\\\x" = \cfrac{2}{2} \\\\\\x" = 1$