Question

Calcule as potencias em IR quando definidas :

A-) (1/2) 1/2

B-) 2 sobre 4/3

Answer 1

$a) \ (\frac{1}{2})^{\frac{1}{2}}=\sqrt{\frac{1}{2}}=\frac{\sqrt1}{\sqrt2}=\frac{1}{\sqrt2}=\frac{\sqrt2}{2}\\ \\ b) \ 2^{\frac{4}{3}}= \sqrt[3]{2^4}= \sqrt[3]{16}=2 \sqrt[3]{2}$