Question

calcule as potências de expoente negativo

Me ajudem é pra hj ainda ​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{a)\:2^{-1} = \left(\dfrac{1}{2}\right)^1 = \left(\dfrac{1}{2}\right)}$

$\mathsf{b)\:2^{-2} = \left(\dfrac{1}{2}\right)^2 = \left(\dfrac{1}{4}\right)}$

$\mathsf{c)\:(-2)^{-2} = \left(\dfrac{1}{-2}\right)^2 = \left(\dfrac{1}{4}\right)}$

$\mathsf{d)\:(-2)^{-3} = \left(\dfrac{1}{-2}\right)^3 = \left(-\dfrac{1}{8}\right)}$

$\mathsf{e)\:\left(\dfrac{1}{2}\right)^{-1} = \left(\dfrac{2}{1}\right)^1 = 2}$

Answer 2

a)2^(-1)=1/2

b) 2^(-2)=1/2²=1/4=0,25

c) (-2)^(-2) =1/(-2)²=1/4=0,25

d) (-2)^(-3)=1/(-2)³=1/(-8)=-1/8=-0,125

e) (1/2)^(-1)=2