Question

calcule as potências com expoentes inteiros em R.
$( { 2.5})^{3}$
$( - 2) ^{3}$
$(1 \times \frac{1}{2}) ^{3}$
${ - 2}^{6}$

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Answer 1

• R = $\frac{25}{4}$

${( 2, 5 )}^{2}$ =

($\frac{5}{2})^{2}$ =

= $\frac{25}{4}$

• R = - 8

${( - 2 )}^{3}$

${-2}^{3}$

- ( 2 . 2 . 2 )

- 8

• R = $\frac{1}{8}$

(1 . $\frac{1}{2})^{3}$

($\frac{1}{2})^{3}$

$\frac{1}{8}$

• R = - 64

${( - 2 )}^{6}$

- ( 2 . 2 . 2 . 2 . 2 . 2 )

- 64