Question

calcule as potências:

alguem me ajuda porfavor ​

Answer 1

Explicação passo-a-passo:

A)

$10 {}^{ - 2} = \frac{1}{10 {}^{2} } \\ 10 {}^{2} = 10 \times 10 = 100 \\ \frac{1}{100}$

B)

$- (\frac{5}{8}) {}^{ - 2} = ( - \frac{8}{5}) {}^{2} \\ ( - \frac{8}{5}) {}^{2} = ( \frac{8}{5}) {}^{2} = \frac{8 {}^{2} }{5 {}^{2} } = \frac{64}{5 {}^{2} } \\ \frac{64}{25}$

C)

$(- \frac{ 3 }{ 2 } ) ^ { -3 } = ( - \frac{2}{3}) {}^{3} \\ ( - \frac{2}{3}) {}^{3} = - ( \frac{2}{3}) {}^{3} = - \frac{2 {}^{3} }{3 {}^{3} } = \frac{8}{3 {}^{3} } \\ - \frac{8}{27}$

D)

$( - 3) {}^{ - 3} = - 3 {}^{ - 3} \\ - \frac{1}{3 {}^{3} } \\ 3 {}^{3} = 3 \times 3 \times 3 = 27 \\ \frac{1}{27}$

E)

$( + \frac{2}{3}) {}^{ - 2} = ( \frac{3}{2}) {}^{2} \\ ( \frac{3}{2}) {}^{2} = \frac{3 {}^{2} }{2 {}^{2} } = \frac{9}{2 {}^{2} } \\ \frac{9}{4}$

F)

$( + \frac{1}{2} ) {}^{ - 5} = ( \frac{1}{2}) {}^{5} \\ 2 {}^{5}$

G)

$( - 0.5) {}^{ - 3} = 0.5 {}^{ - 3} \\ ( \frac{1}{2}) {}^{ - 3} = 2 {}^{3} \\ 2 {}^{3} = 2 \times 2 \times 2 = 8$

H)

$( \frac{2}{3}) {}^{ - 1} = \frac{3}{2}$

I)

$( \frac{1}{10}) {}^{2} = \frac{1 {}^{2} }{10 {}^{2} } \\ \frac{1}{10 {}^{2} } = 10 \times 10 = 100 \\ \frac{1}{100}$

J)

$(2.5) {}^{2} = ( \frac{5}{2}) {}^{2} \\ \frac{5 {}^{2} }{2 {}^{2} } = \frac{25}{2 {}^{2} } \\ \frac{25}{4}$

K)

$( - 0.2) {}^{ - 5} = ( - \frac{1}{2}) {}^{ - 5} \\ ( - 5) {}^{ 5} = - 5 {}^{5} = - (5 \times 5 \times 5 \times 5 \times 5) \\ - 3125$