Question

calcule as potencias
A) (5x)³
B) (2/3x²)⁴
C)(m⁵y4/2)⁶
D) [(-2m³x⁴)²]²

Answer 1

Resposta:

A) (5x) ³ = (5x) •(5x) •(5x) = 125x³

B) (2/3x²)⁴ = (16 /81x⁸)

se for:

(2²/3x²)⁴ fica :

(2⁸/3⁴x⁸) = 256/81x⁸

C) (m⁵4y/2)⁶

= m³⁰4⁶y⁶/2⁶ = m³⁰4096y⁶/64 =

64m³⁰y⁶

d) [(-2m³x⁴)²]² =

(-2m³x⁴)⁴ =

(-2m³x⁴)(-2m³x⁴)(-2m³x⁴)(-2m³x⁴) =

(4m⁶ -2m³x⁴-2m³x⁴ + x⁸ )² =

(4m⁶ - 4m³x⁴ + x⁸)(4m⁶ -4m³x⁴ + x⁸)=

16m¹²-16m⁹x⁴+4m⁶x⁸-16m⁹x⁴+16m⁶x⁸-4m³x¹²+4m⁶x⁸-4m³x¹²+x¹⁶ =

16m¹² (-16m⁹x⁴-16m⁹x⁴) (+4m⁶x⁸+16m⁶x⁸ + 4m⁶x⁸) (-4m³x¹²-4m³x¹²) + x¹⁶

16m¹² - 32m⁹x⁴ + 24m⁶x⁸ - 8m³x¹² + x¹⁶

Answer 2

Explicação passo-a-passo:

a)(5x)^3 = 125x^3

b)(2/3x^2)^4 = (2/3x)^8

c)(m^5y4/2)^6 = m^30 + y^6 + 4/2^6