Question

calcule as potencias;
a) 3⁴
b) 2⁵
c) 1⁴
d) 0⁶
e) (-2)⁴
f abaixo)

( 3 ³
-
(4

g abaixo
( -2 ³
-
3)

h) 5 ⁰
i) (2,43) ⁰
j) (-0,5) ⁰
k) 17¹
l) (1,45)¹
m) (-5)¹

n abaixo
(-4¹
-
7)

o) 3-¹
p) (-3)²
q) 2-¹
r abaixo

( 2²
-
3)

Answer 1

Resposta:

a) 81

b) 32

c) 1

d) 0

e) -16

f) 19683

g) 512

h) 1

i) 1

j) 1

k) 17

l) 1,45

m) -5

n) -4

o) 3

p) -27

q) 2

r) 4

Explicação passo-a-passo:

Answer 2

Explicação passo-a-passo:

$a)~~3^4=3.3.3.3=81\\ \\ b)~~2^5=2.2.2.2.2=32\\ \\ c)~~1^4=1.1.1.1=1\\ \\ d)~~0^6=0.0.0.0.0.0=0\\ \\ e)~~(-2)^4=(-2)(-2)(-2)(-2)=+16\\ \\ f)~~({3\over4})^3=({3\over4})({3\over4})({3\over4})={27\over64}\\ \\ g)~~~(-{2\over3})^3=(-{2\over3})(-{2\over3}(-{2\over3})=-{8\over27}\\ \\ h)~~5^0=1\mapsto todo~~n\'umero~~elevado~~a~~zero=1\\ \\ i)~~(2,43)^0=1\\ \\ j)~~(-0,5)^0=1\\ \\ k)~~17^1=17\\ \\ l)~~(1,45)^1=1,45\\ \\ m)~~(-5)^1=-5\\ \\ n)~~(-{4\over7})^1=-{4\over7}\\ \\ o)~~3^{-1}={1\over3}$

$p)~~(-3)^2=(-3)(-3)=+9\\ \\ q)~~2^{-1}={1\over2}\\ \\ r)~~({2\over3})^2=({2\over3})({2\over3})={4\over9}$