Question

Calcule as potências:
a) 2^5=
b) (-3)^4=
c)(3/4)^3=
d)(0,9)^2=
e)(-2,5)^2=
f) 4^-2=
g)(-3)^-2=
h)(3/4)^-2=
i)(-0,1)11=

Answer 1

2.2.2.2.2=32
-3.-3.-3.-3=81
3³/4³=27/64
(9/10)²=81/100=0,81
(-25/10)²=625/100=6,25
4*-2= (1/4)²=1/16
(-3)*-2=(1/-3)²=1/9
(3/4)*-2=(4/3)²=16/9
A última eu não sei lhe responder

Answer 2

A) $2^5= 2.2.2.2.2 = 32$

B) $(-3)^4 = (-3).(-3).(-3).(-3) = 81$

C) $(\frac{3}{4} )^3 = \frac{3}{4} . \frac{3}{4} . \frac{3}{4} = \frac{27}{64}$

D) $(0,9)^2 = (0,9) . (0,9) = 0,81$ 

E) $(-2,5)^2 = (-2,5) . (-2,5) = 6,25$

F) $4^{-2} = ( \frac{1}{4} )^2 = \frac{1^2}{4^2}}} = \frac{1}{16}$

G) $(-3)^{-2}= (\frac{1}{3})^2 = \frac{1^2}^{3^2}} = \frac{1}{9}$

H) $( \frac{3}{4})^{-2} = ( \frac{4}{3} )^2 = \frac{4^2}{3^2} } = \frac{16}{9}$

I) $(-0,1)^{11} = (-0,1)$