Question

Calcule as potencias.

a) (2/3)²=
b) (10/11)²=
c) (1/5)²=
d) (7/5)²=

Calcule a raiz quadrada.

√16/144=

Answer 1

Bom dia!

a) (2/3)²= 2²/3² = 4/9

b) (10/11)²= 10²/11² = 100/121

c) (1/5)²= 1²/5² = 1/25

d) (7/5)²= 7²/5² = 49/25

$\sqrt{ \frac{16}{144} } = \frac{ \sqrt{16} }{ \sqrt{144} } = \frac{4}{12} = \frac{1}{3}$

Espero ter ajudado!

Bons estudos!

Answer 2

a)

$( { \frac{2}{3} )}^{2} = \frac{2 {}^{2} }{ {3}^{2} } = \frac{4}{9}$

b)

${( \frac{10}{11} )}^{2} = \frac{ {10}^{2} }{ {11}^{2} } = \frac{100}{121}$

c)

${( \frac{1}{5}) }^{2} = \frac{ {1}^{2} }{ {5}^{2} } = \frac{1}{25}$

d)

${( \frac{7}{5} )}^{2} = \frac{ {7}^{2} }{ {5}^{2} } = \frac{49}{25}$

2)

$\sqrt{ \frac{16}{144} } = \sqrt{ \frac{1}{9} } = \frac{1}{3}$

$\frac{ \sqrt{16} }{144} = \frac{4}{144} = \frac{1}{36}$