Question

calcule as potências.

a) (1/4)-²
b) (-5/4)-³
c) 10-²
d) 2-¹
e) (-6)-²
f) (1/9)-²​

Answer 1

Resposta:

$a)\\ \\ (\frac{1}{4})^{-2} =\frac{1}{(\frac{1}{4})^{2} } =\frac{1}{\frac{1}{16} } =1. \frac{16}{1} =16\\ \\ b)\\ \\ (-\frac{5}{4} )^{-3} =\frac{1}{(-\frac{5}{4})^{3} } =\frac{1}{-\frac{125}{64} } =1.-\frac{64}{125} =-\frac{64}{125} \\ \\ c)\\ \\ 10^{-2} =\frac{1}{10^{2} } =\frac{1}{100} ~~ou=0,01$

$d)\\ \\ 2^{-1} =\frac{1}{2^{1} }=\frac{1}{2} ~~ou=0,5\\ \\ e)\\ \\- 6^{-2} =\frac{1}{-6^{2} } =\frac{1}{36} \\ \\ f)\\ \\ (\frac{1}{9} )^{-2} =\frac{1}{(\frac{1}{9})^{2} } =\frac{1}{\frac{1}{81} } =1.\frac{81}{1} =81$