Matemática, perguntado por Abnerit50, 8 meses atrás

Calcule as Potências

Anexos:

Soluções para a tarefa

Respondido por ToquioItuno
2

\Large\boxed{\boxed{\boxed{{Ola\´\ }}}}}

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a)

  • \sf 7^{3} \:>>>\:7\times7\times7=\large\boxed{{\sf \blue3\blue4\blue3{}}}\\

b)

  • \sf 5^{0} =\large\boxed{{\sf \blue1{}}}\\

c)

  • \sf(-4)^{2} \:>>>\:4^{2} \:>>>\:4\times4=\large\boxed{{\sf \blue1\blue6{}}}\\

d)

  • \sf (\frac{1}{2} )^{4} \:>>>\:\frac{1^{4} }{2^{4} } \:>>>\:\frac{1\times1\times1\times1}{2\times2\times2\times2} =\large\boxed{{\sf \frac{\blue1}{\blue1\blue6} {}}}\\

e)

  • \sf9^{\frac{1}{2} } \:>>>\:(3^{2} )^{\frac{1}{2} } \:>>>\:3^{2\times\frac{1}{2} } \:>>>\:3^{1} =\large\boxed{{\sf \blue3{}}}\\

f)

  • \sf0^{\frac{3}{8} } =\large\boxed{{\sf \blue0{}}}\\

g)

  • \sf2^{1\frac{1}{3} }\:>>>\:2\frac{1.3+1}{3} \:>>>\:2\frac{3+1}{3} \:>>>\:2\frac{4}{3} \:>>>\: \sf \sqrt[\sf3]{\sf2^{\sf4} } \:\sf >>>\:\sqrt[3]{2^{3}\times2 } \:>>>\:\sf \sqrt[3]{2^{3} } \sf \sqrt[3]{\sf2} =\large\boxed{{\sf \blue2\sqrt[\blue3]{\blue2} {}}}\\

h)

  • \sf8^{0,6666} \:>>>\:8^{\frac{3333}{5000} } \:>>>\:\sf \large\boxed{{\sf \sqrt[\blue5 \blue0 \blue0 \blue0]{\sf \blue8^{ \blue3 \blue3 \blue3 \blue3} } {}}}\\
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