Question

calcule as potências
(3/4)-2
(-5/4)-3
${10}^{ - 3}$
${2}^{ - 1}$
(-6)-2
( 1/9)-2​

Answer 1

Oie, Td Bom?!

➣ $( \frac{3}{4} ) {}^{ - 2} = ( \frac{4}{3} ) {}^{2} = \frac{4 {}^{2} }{3 {}^{2} } = \frac{16}{9}$

➣ $( - \frac{5}{4} ) {}^{ - 3} = ( - \frac{4}{5} ) {}^{3} = - ( \frac{4}{5} ) {}^{3} = - \frac{4 {}^{3} }{5 {}^{3} } = - \frac{64}{125}$

➣ $10 {}^{ - 3} = \frac{1}{10 {}^{3} } = \frac{1}{1000}$

➣ $2 {}^{ - 1} = \frac{1}{2}$

➣ $( - 6) {}^{ - 2} = 6 {}^{ - 2} = \frac{1}{6 {}^{2} } = \frac{1}{36}$

➣ $( \frac{1}{9} ) {}^{ - 2} = 9 {}^{2} = 81$

Att. Makaveli1996

Answer 2

a) (3/4)⁻² = (4/3)² = (4.4)/(3.3) = 16/3

b) (-5/4)⁻³ = (-4/5)³ = (4.4.4)/(-5.-5.-5) = 64/125

c) (10)⁻³ = (1/10)³ = 1000

d) 2⁻¹ = 1/2

e) (-6)⁻² = (-1/6)² = (-1.-1)/(6.6) = 1/36

f) (1/9)⁻² = (9/1)² = 9.9 = 81