Question

calcule as potências [(-2m^3x^4)^2]^2

Answer 1

$c) \\ ( \frac{m^5y^4}{2} )^6= \frac{m^{30}y^{24}}{64} \\ \\ d) \\ .[(-2m^3x^4)^2]^2= \\ \\ (+4m^6x^8)^2= \\ \\ 16m^{12}x^{16}$