Question

Calcule as potências ​

Answer 1

Resposta:

$j) (\frac{1}{7} )^{2} = \frac{1}{49} \\ \\ k) (\frac{4}{3} )^{4} = \frac{256}{81} \\ \\ l)( \frac{2}{9} ) ^{1} = \frac{2}{9} \\ \\ m) (\frac{3}{12} ) ^{2} = \frac{9}{144} \\ \\ n) (\frac{5}{4} ) ^{0} = 1 \\ \\ o) (\frac{11}{12} ) ^{2} = \frac{121}{144} \\ \\ p)( \frac{1}{4} ) ^{2} = \frac{1}{16} \\ \\ q) ( \frac{3}{7})^{3} = \frac{27}{343}$

espero ter ajudado ♡