Matemática, perguntado por bcdp2712, 5 meses atrás

Calcule as potencias

(+1/3)2

(-1/5)2

(+2/3)2

(-3/7)2

(+4/5)2

(-3/2)2

(-8/3)2

(-1/4)2

(-2/3)3

Soluções para a tarefa

Respondido por or864095274
0

Resposta:

(+1/3)²=1/9

(-1/5)²=1/25

(+2/3)²=4/9

(-3/7)²=9/49

(+4/5)²=16/20

(-3/2)²=9/4

(-8/3)²=64/9

(-1/4)2=1/16

(-2/3)³=-8/27

(+1/3)²=1/9 \\ </strong></p><p></p><p><strong>[tex](+1/3)²=1/9 \\ (-1/5)²=1/25 \\ </strong></p><p></p><p><strong>[tex](+1/3)²=1/9 \\ (-1/5)²=1/25 \\ (+2/3)²=4/9 \\ </strong></p><p></p><p><strong>[tex](+1/3)²=1/9 \\ (-1/5)²=1/25 \\ (+2/3)²=4/9 \\ (-3/7)²=9/49 \\ </strong></p><p></p><p><strong>[tex](+1/3)²=1/9 \\ (-1/5)²=1/25 \\ (+2/3)²=4/9 \\ (-3/7)²=9/49 \\ (+4/5)²=16/20 \\ </strong></p><p></p><p><strong>[tex](+1/3)²=1/9 \\ (-1/5)²=1/25 \\ (+2/3)²=4/9 \\ (-3/7)²=9/49 \\ (+4/5)²=16/20 \\ (-3/2)²=9/4 \\ </strong></p><p></p><p><strong>[tex](+1/3)²=1/9 \\ (-1/5)²=1/25 \\ (+2/3)²=4/9 \\ (-3/7)²=9/49 \\ (+4/5)²=16/20 \\ (-3/2)²=9/4 \\ (-8/3)²=64/9 \\ </strong></p><p></p><p><strong>[tex](+1/3)²=1/9 \\ (-1/5)²=1/25 \\ (+2/3)²=4/9 \\ (-3/7)²=9/49 \\ (+4/5)²=16/20 \\ (-3/2)²=9/4 \\ (-8/3)²=64/9 \\ (-1/4)2=1/16 \\ </strong></p><p></p><p><strong>[tex](+1/3)²=1/9 \\ (-1/5)²=1/25 \\ (+2/3)²=4/9 \\ (-3/7)²=9/49 \\ (+4/5)²=16/20 \\ (-3/2)²=9/4 \\ (-8/3)²=64/9 \\ (-1/4)2=1/16 \\ (-2/3)³=-8/27 \\

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