Question

calcule as potência............

Answer 1

a) (1/3)² = 1/3 *1/3 = 1/9    /    b) (-1/5)³ = (-1/5)*(-1/5)*(-1/5) = -1/125
c)  (Inverte a fração para o expoente ficar positivo) (2/1)³ = 2³ = 2*2*2 = 8
d) 0,5 -³ = 5/10 -³ = 10/5 ³ =  (10/5)*(10/5)*(10/5) = 1000/125
e) (-2/1)³ = -2³ = (-2)*(-2)*(-2) = -8
f)  (-1,2) -¹ = (-12/10)-¹= (10/12)¹= 10/12 
g) (5/1)-³ = (1/5)³ = (1/5)*(1/5)*(1/5) = 1/125

Answer 2

Resposta:

$a)3^{-2} = \frac{1}{3^{2} } =\frac{1}{9}$

$b)(-5)^{-3} =-5^{-3} =-\frac{1}{5^{3} } =\frac{1}{125}$

$c)(-\frac{1}{2} )^{-3} =(-2)^{3} =-8$

$d)0,5^{-3} =(\frac{1}{2} )^{-3} =2^{3} =8$

$e)(-\frac{1}{2} )^{-3} =(-2)^{3} =-8$

$f)(1,2)^{-1} =0,83$

$g)5^{-3} = 0,008$