Question

calcule as pontenciação com expoente positivo.​

Answer 1

Resposta:


Explicação passo a passo:
a)
(-3/5)^2=9/25


b)
(0,3)^4
= (0,09).(0,09)
= 0,0081

c))
(-0,14)^2= 0,0196

D)
(-1/1000)^2 = 1/1000000

E)
(-3/4)^3 = - 27/64

F)
(-1/10)^5 = -1/100000

G)
(1/3)^5 = 1/243

H)
(2/7)^3= 8/343

Answer 2

Explicação passo-a-passo:

$a)( - \frac{3}{5} ) {}^{2} = - \frac{3}{5} . - \frac{3}{5} = \frac{9}{125}$

$b)(0.3) {}^{4} = 0.3 \times 0.3 \times 0.3 \times 0.3 = 0.0081$

$c)( - 0.14) {}^{2} = - 0.14 \times - 0.14 = - 0.196$

$d)( \frac{1}{1.000} ) {}^{2} = \frac{1}{1.000} \times \frac{1}{1.000} = \frac{1}{1.000.000}$

$e)( - \frac{3}{4} ) {}^{3} = - \frac{3}{4} . - \frac{3}{4} . - \frac{3}{4} = - \frac{27}{64}$

$f)( - \frac{1}{10} ) {}^{5} = - \frac{1}{10} . - \frac{1}{10} . - \frac{1}{10} . - \frac{1}{10} . - \frac{1}{10} = - \frac{1}{100.000}$

$g)( \frac{1}{3} ) {}^{5} = \frac{1}{3} . \frac{1}{3} . \frac{1}{3} . \frac{1}{3} . \frac{1}{3} = \frac{1}{243}$

$h)( \frac{2}{7} ) {}^{3} = \frac{2}{7} . \frac{2}{7} . \frac{2}{7} = \frac{8}{343}$