Question

calcule as medidas de abertura dos quatros ângulos internos de cada paralelogramo

Answer 1

Resposta:

a) 3x+22=5x

22=5x-3x

22=2x

x=22/2

x=11

•3.11 + 22 = 55°

•5.11 = 55°

b)x/2+30=x-15

x/2 + 60/2 = 2x/2 - 30/2

x+60= 2x - 30

60+30= 2x-x

90=x

•90/2+30= 75°

•90-15= 75°