Question

CALCULE AS MASSAS MOLECULARES DAS SUBSTANCIAS ABAIXO:

A) C2H6
B) SO2
C)CaCO3
D)NaHSO4
E)CH3 COONa
F)(NH4)PO4
G)Fe4[Fe(CN)6]3
H)Na2 CO3.10H20
I)Na4P2O7
J)C0S04.SH20

Answer 1

 

A)C2H6: (2x12 + 6x1) = 30g/mol 
B)SO2:(1x32,1 + 2x16) = 64,1g/mol 
C)CaCO3: (1x40,1+ 1x12 + 3x16) = 100,1g/mol 
D)NaHSO4: (1x23 + 1x1 + 1x32,1 + 4x16) = 120,1g/mol 
E)CH3COONa: (1x12 + 3x1 + 1x12 + 2x16 + 1x23) = 82g/mol 
F)(NH4)3PO4: (3x14 + 12x1 + 1x31 + 4x16) = 149g/mol 
G)Fe4[Fe(CN)6]3: (4x56 + 3x56 + 18x12 + 18x14) = 860g/mol 
H)Na2CO3 x 10H2O: (2x23 + 1x12 + 3x16) + (20x1 + 10x16) = 286g/mol 

Answer 2

Resposta:

A)C2H6: (2x12 + 6x1) = 30g/mol 

B)SO2:(1x32,1 + 2x16) = 64,1g/mol 

C)CaCO3: (1x40,1+ 1x12 + 3x16) = 100,1g/mol 

D)NaHSO4: (1x23 + 1x1 + 1x32,1 + 4x16) = 120,1g/mol 

E)CH3COONa: (1x12 + 3x1 + 1x12 + 2x16 + 1x23) = 82g/mol 

F)(NH4)3PO4: (3x14 + 12x1 + 1x31 + 4x16) = 149g/mol 

G)Fe4[Fe(CN)6]3: (4x56 + 3x56 + 18x12 + 18x14) = 860g/mol 

H)Na2CO3 x 10H2O: (2x23 + 1x12 + 3x16) x (20x1 + 10x16) = 19.080g/mol

J)COSO4.SH2O: (12+16+32+16X4)x(32+1x2+16)= 6.200g/mol