Question

Calcule as massas moleculares.
(1) Ni(OH2):
(2) (NH4)3 Fe(CN)6:
(3) Bi(SO3)3
(4) Fe4(P207)3
(5) Al2(C2O4)3

Answer 1

1) MM(Ni) = 59u
    MM{(OH)2} = 2*16 + 2*1 = 34u

    MM{Ni(OH)2} = 59 + 34 = 93u

2) MM{(NH4)3} = 3*14 + (4*1)*3 = 54u

    MM(Fe) = 56u
    MM{(CN)6} = 6*12 + 6*14 = 156u

    MM{Fe(CN)6} = 56 + 156 = 212u

3) MM(Bi) = 209u
    MM{(SO3)3} = 3*32 + (3*16)*3 = 240u
   
    MM{Bi(SO3)3} = 209 + 240 = 449u

4) MM(Fe4) = 224u
    MM{(P2O7)3} = (2*31)*3 + (7*16)*3 = 522u

    MM{Fe4(P2O7)3} = 224 + 522 = 746u

5) MM(Al2) = 2*27 = 54u
    MM{(C2O4)3} = (2*12)*3 + (4*16)*3 = 264u

    MM{Al2(C2O4)3} = 54 + 264 = 318u