Question

Calcule as integrais indefinidas ∫ (t − 9)2 dt

Answer 1

Olá !

Calculando a integral de (t - 9)^2dt.

$\mathsf{\displaystyle\int(t-9)^{2}dt} \\\\\\ \mathsf{\displaystyle\int(t-9)^{2}dt=\dfrac{(t-9)^{(2+1)}}{(2+1)}} \\\\\\ \mathsf{\displaystyle\int(t-9)^{2}dt=\dfrac{(t-9)^{3}}{3}+C}$

Resultado final :

$\boxed{\mathsf{\displaystyle\int(t-9)^{2}dt=\dfrac{(t-9)^{3}}{3}+C}}$

Espero ter colaborado !