Question

calcule as frações abaixo ​

Answer 1

$\large\boxed{\begin{array}{l}\sf a)~\rm\dfrac{\backslash\!\!\!3^1}{7}\cdot\dfrac{8}{\backslash\!\!\!9_3}=\dfrac{1\cdot8}{7\cdot3}=\dfrac{8}{21}\\\\\sf b)~\rm\dfrac{1}{4}\cdot\dfrac{5}{7}=\dfrac{1\cdot5}{4\cdot7}=\dfrac{5}{28}\\\\\sf c)~\rm\dfrac{2}{9}\div\dfrac{3}{6}=\dfrac{2}{\backslash\!\!\!9_3}\cdot\dfrac{\backslash\!\!\!6^2}{3}=\dfrac{2\cdot2}{3\cdot3}=\dfrac{4}{9}\end{array}}$

$\large\boxed{\begin{array}{l}\sf d)~\rm\dfrac{3}{5}\div\dfrac{9}{27}=\dfrac{\backslash\!\!\!3^1}{5}\cdot\dfrac{27}{\backslash\!\!\!9_3}=\dfrac{\diagdown\!\!\!\!\!\!27^9}{5\cdot\backslash\!\!\!3}=\dfrac{9}{5}\\\\\sf e)~\rm\dfrac{9}{4}+\dfrac{1}{2}=\dfrac{9+2}{4}=\dfrac{11}{4}\\\\\sf f)~\rm\dfrac{1}{3}+\dfrac{7}{6}=\dfrac{2+7}{6}=\dfrac{9\div3}{6\div3}=\dfrac{3}{2}\end{array}}$

$\large\boxed{\begin{array}{l}\sf g)~\rm\dfrac{10}{4}-\dfrac{3}{16}=\dfrac{40-3}{16}=\dfrac{37}{16}\\\\\sf h)~\rm\dfrac{3}{5}-\dfrac{9}{15}=\dfrac{3}{5}-\dfrac{3}{5}=0\end{array}}$