Question

calcule as expressoes y=(3^4:3^2)^2-(2^4:2^2)^2

Answer 1

y=(3^4:3^2)^2-(2^4:2^2)^2

y=(3^(4-2)^2-(2^(4-2)^2

y=(3^(2)^2-(2^2)^2

y= 3^4 - 4^2

y = 81 - 16  ==> y = 65