Question

calcule as expressões trigonométricas :
a) sen30°+cos270°-sen90°
b)cos45°-sen60°+cos60°
c)sen180°-cos360°+sen30°
d)tg45°-sen270°+cos180°-sen90°
e)sen45°-cos90°+sen150+sen300°

Answer 1

Oie, Td Bom?!

a)

= sen(30°) + cos(270°) - sen(90°)

= 1/2 + 0 - 1

= 1/2 - 1

= [1 - 2]/2

= - 1/2

b)

= cos(45°) - sen(60°) + cos(60°)

= √2/2 - √3/2 + 1/2

= [√2 - √3 + 1]/2

c)

= sen(180°) - cos(360°) + sen(30°)

= 0 - 1 + 1/2

= - 1 + 1/2

= [- 2 + 1]/2

= - 1/2

d)

= tan(45°) - sen(270°) + cos(180°) - sen(90°)

= 1 - (- 1) - 1 - 1

= - (- 1) - 1

= 1 - 1

= 0

e)

= sen(45°) - cos(90°) + sen(150°) + sen(300°)

= √2/2 - 0 + 1/2 - √3/2

= √2/2 + 1/2 - √3/2

= [√2 + 1 - √3]/2

Att. Makaveli1996

Answer 2

Resposta:

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Explicação passo-a-passo:

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