Matemática, perguntado por gilmoraes198, 6 meses atrás

calcule as expressoes algebricas [(1\8 + 1\5) : (2\6 + 1\16)] + 0,125​

Soluções para a tarefa

Respondido por simonesantosaraujo91
0

Resposta:

719/760

Explicação passo-a-passo:

((1/8+1/5)÷(2/6+1/16))+0,125=

(1/8+1/5)÷(2/6+1/16)+0,125

1/8+1/5

5+8/40

13/40

(1/8+1/5)÷(2/6+1/16)+0,125

13/40÷(2/5+1/16)+0,125

(1/8+1/5)÷(2/6+1/16)+0,125

(2/6+1/16)

2/6+1/16 risque o numero 6

3/1+1/16

16+3/48

19/48

(1/8+1/5)÷(2/6+1/16)+0,125

13/40÷19/48+0,125

(1/8+1/5)÷(2/6+1/16)+0,125

0,125

125/1000

125/1000 risque os dois numeros 125 e 1000

1/8

(1/8+1/5)÷(2/6+1/16)+0,125

13/40÷18/48+1/8

13/40×48/19+1/8

13/40×48/19+1/8 risque os numeros 40 e 48

13/5×6/19+1/8

13/5×6/19

13×6/5×19

13×6/5×19 13×6/5×19

78/5×19 78/95

13/5×6/19+1/8

7/9 8/5 +1/8

624+95/760

719/760

78/95+1/8

719/760

Resposta

719/760

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