Question

calcule as expressões abaixo
A) (2^3)×(2^-2)=

B) (3^2)÷(3^-2)​

Answer 1

→ Cálculo :

$\boxed{\begin{array}{lr} \mathrm{N)}\\\\\large{2^{3}\times2^{-3} =}\\ \\\large{2^{3-3} = } \\\\\large{2^{0} =}\\\\\large\boxed{{\red{ 1}}}\end{array}}$

$\boxed{\begin{array}{lr} \mathrm{O)}\\\\\large{3^{2}\div3^{-2} =}\\ \\\large{3^{2+2} = } \\\\\large{3^{4} =}\\\\\large\boxed{{\red{ 81}}}\end{array}}$

Att, PurpleStars ❤️

Answer 2

Resposta:

Explicação passo-a-passo:

A)

2^3 . 2^(-3)

= 2^(3-3)

= 2^0

= 1

B)

3^2 : 3^(-2)

= 3^[2-(-2)]

= 3^(2+2)

= 3^4

= 81