Question

calcule as divisões.

A) ³√4 : √2


B)⁵√16 : ³√4


C)⁶√10 : ⁴√9


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Answer 1

$a) \sqrt[3]{4} \div \sqrt{2} = \sqrt[5]{ \frac{4}{2} } = \sqrt[5]{2}$

.

$\sqrt[5]{16} \div \sqrt[3]{4} = \sqrt[8]{ \frac{16}{4} } = \sqrt[8]{4}$

$c) \sqrt[6]{10} \div \sqrt[4]{9} = \sqrt[10]{ \frac{10}{9} }$

Answer 2

Explicação passo-a-passo:

A)

$\sqrt[3]{4} \div 2$

=>³√4/2

B)

$\sqrt[5]{16} \div \sqrt[3]{4}$

$\sqrt[15]{16 {}^{3} } \div \sqrt[15]{4 {}^{5} }$

$\sqrt[15]{16 {}^{3} \div 4 {}^{5} }$

$\sqrt[15]{4 {}^{6} \div 4 {}^{5} }$

=>¹⁵√4

C)

$\sqrt[6]{10} \div \sqrt[4]{9}$

$\sqrt[12]{10 {}^{2} } \div \sqrt[12]{9 {}^{3} }$

$\sqrt[12]{10 {}^{2} \div 9 {}^{3} }$

$\sqrt[12]{ \dfrac{10 {}^{2} }{9 {}^{3} } }$

$\sqrt[12]{ \dfrac{100}{729} }$

$\sqrt[12]{( \dfrac{10}{27} ) {}^{2} }$

$\sqrt[6]{ \dfrac{10}{27} }$

$\dfrac{ \sqrt[6]{10} }{ \sqrt[6]{27} }$

$\dfrac{ \sqrt[6]{10} }{ \sqrt[6]{3 {}^{3} } }$

$\dfrac{ \sqrt[6]{10} }{ \sqrt{3} }$

$\dfrac{ \sqrt[6]{10} \sqrt{3} }{3}$

$\dfrac{ \sqrt[6]{10} \sqrt[6]{3 {}^{3} } }{3}$

$\dfrac{ \sqrt[6]{10 \times 3 {}^{3} } }{3}$

$\dfrac{ \sqrt[6]{10 \times 27} }{3}$

=>⁶√270/3