Question

Calcule as coordenadas do vértice das seguintes funções:

a) f(x) = x2 + 10x + 24

b) f(x) = x2 - 11x + 24

c) f(x) = 3x2 + 12x + 10

Answer 1

a) x^2+10x+24=0
delta=b^2-4ac
delta=10^2-4.1.24
delta=100-96
delta=4
xv=-b/2a
xv=-10/2.1
xv=-10/2
xv=-5
yv=-delta/4a
yv=-4/4.1
yv=-4/4
yv=-1
b) x^2-11x+24=0
delta=b^2-4ac
delta=(-11)^2-4.1.24
delta=121-96
delta=25
xv=-b/2a
xv=-(-11)/2.1
xv=11/2
yv=-delta/4a
yv=-25/4.1
yv=-25/4
c) 3x^2+12x+10=0
delta=b^2-4ac
delta=12^2-4.3.10
delta=144-120
delta=24
xv=-b/2a
xv=-12/2.3
xv=-12/6
xv=-2
yv=-delta/4a
yv=-24/4.3
yv=-24/12
yv=-2