Question

Calcule as coordenadas do ponto Médio M do segmento AB nos casos:A(1,-2) e B(-3,1)

Answer 1

$A(1,-2) e B(-3,1)\\ M_{A} = \frac{(x_{a} +x_{b})}{2} =M_{A} = \frac{1 +(-3)}{2} =-1 \\ M_{B} = \frac{(y_{a} +y_{b})}{2} =M_{B} = \frac{(-2) +1}{2}= -\frac{1}{2} \\M(-1.-\frac{1}{2} )$