Question

Calcule:

a)
$co log_{ \sqrt{2} }(8)$

b)
${2}^{2 + 2 log_{2}(5) }$
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Answer 1

Resposta:

a) -6 b) 100

Explicação:

a)

$colog_\sqrt{2}}(8) = - log_\sqrt{2}}(8) = x\\\sqrt{2}^- ^- ^x = 8\\2^{\frac{-x}2} = 2^3\\\frac{-x}{2} = 3\\x =-6$

b)

$2^{2+2log__2}5} = 4.2^{2log__2}5} = 4.2^{log__2}5^2}=4.5^2 = 100$