Question

calcule:

a)\sqrt{64+36=}
B)\sqrt{10²+8²}
C)\sqrt{3²+4²}
D)\sqrt{100-36}

Answer 1

$a)\sqrt{64 + 36} = \sqrt{100} = 10$
$b) \sqrt{ {10}^{2} + {8}^{2} } = \sqrt{100 + 64} = \sqrt{164} = 2 \sqrt{41}$
$c) \sqrt{ {3}^{2} + {4}^{2} } = \sqrt{9 + 16} = \sqrt{25} = 5$
$d) \sqrt{100 - 36} = \sqrt{64} = 8$