Question

Calcule a soma dos termos de PA (-2,1,4,....,34)

Answer 1

Resposta:

Sn= 208

Explicação passo a passo:

an=a1+(n-1).r

34=-2+(n-1).3

34=5 .3n

n=39/3

an=13

Sn= (a1+an).n/2

Sn=(-2+34).13/2

Sn=416/2

Sn=208

Answer 2

$> resolucao \\ \\ \geqslant progressao \: \: aritmetica \\ \\ r = a2 - a1 \\ r = 1 - ( - 2) \\ r = 1 + 2 \\ r = 3 \\ \\ an = a1 + (n - 1)r \\ 34 = - 2 + (n - 1)3 \\ 34 = - 2 + 3n - 3 \\ 34 = - 5 + 3n \\ 34 + 5 = 3n \\ 39 = 3n \\ n = \frac{39}{3} \\ n = 13 \\ \\ \\ \geqslant \: soma \: dos \: termos \: da \: pa \\ \\ sn = \frac{(a1 + an)n}{2} \\ \\ sn = \frac{( - 2 + 34)13}{2} \\ \\ sn = \frac{32 \times 13}{2} \\ \\ sn = 16 \times 13 \\ \\ sn = 208 \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant \geqslant$