Calcule a soma dos termos da PG finita (5,10...1280)
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Sn= A1.(1-q^n)
(1-q).
Sn= 5.(1-2^9 ).
(1- 2)
Sn= 5.(1-512)
(-1)
Sn=5.(-511)
( -1)
Sn= 5.511
Sn= 2555
_________________
an=a1.q^n-1
1280=5.2^n-1
1280/5=2^n-1
256=2^n-1
2^8= 2^n-1
corta as bases "2"
8=n-1
n=9
espero ter ajudado !!!!
(1-q).
Sn= 5.(1-2^9 ).
(1- 2)
Sn= 5.(1-512)
(-1)
Sn=5.(-511)
( -1)
Sn= 5.511
Sn= 2555
_________________
an=a1.q^n-1
1280=5.2^n-1
1280/5=2^n-1
256=2^n-1
2^8= 2^n-1
corta as bases "2"
8=n-1
n=9
espero ter ajudado !!!!
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