Question

Calcule a soma dos seis primeiros termos da PG 1,1/3​

Answer 1

Resposta:

a1=1

a2=1/3

q=a2/a1=$\frac{1/3}{1}$

⇒$S=\frac{a1.q^n-1}{q-1}$

S=1.(1/3)^6-1/1/3-1

S=$\frac{-364}{243}$