Question

Calcule a soma dos obze primeiros termos da pg(1/32,1/16,1/18,...).

Answer 1

Olá.

Dados:

$\cdot \: a_{1} = \frac{1}{32} \\ \cdot \: q = \frac{\frac{1}{16}}{\frac{1}{32}} = 2$

$S_{n} = \frac{a_{1} (q^{n} - 1)}{q - 1} \\ \\ S_{11} = \frac{\frac{1}{32}(2^{11} - 1)}{2 - 1} \\ \\ S_{11} = \frac{\frac{1}{32}(2048 - 1)}{1} \\ \\ S_{11} = \frac{\frac{1}{32}(2047)}{1} \\ \\ S_{11} = \frac{2047}{32} \\ \\ S_{11} \approx 64$

Bons estudos.